Independent solution

How to solve this Uniform Distribution question

Setup

Setup

Use the no-deductible expected payment to recover the lower endpoint of the uniform loss distribution.

a+192=10\frac{a+19}{2}=10
a=1a=1

Model

Model

The loss therefore has constant density 1/18 on [1,19], and the second policy pays only the positive excess above 4.

XUniform(1,19)X\sim\operatorname{Uniform}(1,19)
Y=(X4)+Y=(X-4)_+

Compute

Compute

Integrate the payment over the part of the support above the deductible.

E[Y]=419(x4)118dxE[Y]=\int_{4}^{19}(x-4)\frac{1}{18}\,dx
E[Y]=(194)236=6.25E[Y]=\frac{(19-4)^2}{36}=6.25

Answer

Answer

The expected payment under the deductible policy is 6.25.

6.25(B)\boxed{6.25\quad\text{(B)}}