Independent solution

How to solve this Insurance Payment Variables question

Setup

Setup

Let the insurer payment under deductible d be the positive excess above d.

Y=(Xd)+Y=(X-d)_+

Model

Model

Integrate the payment against the uniform density on the part of the loss interval above d.

E[Y]=d100(xd)1100dx=(100d)2200\operatorname{E}[Y]=\int_d^{100}(x-d)\frac1{100}\,dx=\frac{(100-d)^2}{200}

Compute

Compute

Set the expected payment equal to 32 and retain the feasible root.

(100d)2200=32\frac{(100-d)^2}{200}=32
(100d)2=6400(100-d)^2=6400
100d=80,d=20100-d=80,\qquad d=20

Answer

Answer

The deductible is 20.

20(C)\boxed{20\quad\text{(C)}}