Independent solution

How to solve this Uniform Distribution question

Answer in brief

Write the claim payment as the positive part of the loss after the deductible. Integrating its triangular tail gives an expected payment of (500-d)^2/1000; setting this equal to 90 yields d = 200, so the verified answer is choice B.

Setup

Setup

Let X be the loss and d the fixed deductible. The insurer pays only the portion of X that exceeds d.

XUniform(0,500),Y=(Xd)+X\sim\operatorname{Uniform}(0,500),\qquad Y=(X-d)_+

Model

Model

Average the positive excess over the uniform density. A deductible in the support leaves a triangular payment region.

E[Y]=d500(xd)1500dx\mathbb{E}[Y]=\int_d^{500}(x-d)\frac{1}{500}\,dx
E[Y]=(500d)21000\mathbb{E}[Y]=\frac{(500-d)^2}{1000}

Compute

Compute

Equate the stop-loss expectation to the specified expected payment and take the feasible square root.

(500d)21000=90\frac{(500-d)^2}{1000}=90
(500d)2=90,000(500-d)^2=90{,}000
500d=300,d=200500-d=300,\qquad d=200

Answer

Answer

The required fixed deductible is 200 monetary units.

d=200(B)\boxed{d=200\quad\text{(B)}}