Original practice · fully worked
Original variant: courier delay threshold
A courier service models a route's delay T as uniformly distributed between 6 and 18 minutes. A delay is labeled slow when it exceeds the 65th percentile of T. Calculate the amount by which that percentile exceeds the average delay.
- A
-1.8 minutes - B
0.9 minute - C
1.2 minutes - D
1.8 minutes - E
7.8 minutes
Answer and calculation
The 65th percentile is 6 + 0.65(12) = 13.8 minutes, while the uniform mean is 12 minutes. The requested excess is 1.8 minutes, so choice D is correct.
Setup
Setup
Record the interval width and the uniform quantile formula.
T∼Uniform(6,18),18−6=12 qp=6+12p Model
Model
Evaluate the slow-delay threshold and the average delay separately.
q0.65=6+0.65(12)=13.8 E[T]=26+18=12 Compute
Compute
Subtract the average from the percentile as requested.
q0.65−E[T]=13.8−12=1.8 Answer
Answer
The 65th percentile is 1.8 minutes above the average.
1.8 minutes(D)