Original practice · fully worked
Original variant: reverse calibration quantile
An optical scanner's raw calibration score S is uniform, but its endpoints are not listed. Engineers report that Q_S(0.20)=18 and Q_S(0.80)=42. The display converts the score to D=50-0.5S. Determine the 25th percentile of D.
- A
20 - B
25 - C
30 - D
35 - E
40
Answer and calculation
The two supplied quantiles recover S as uniform on [10,50]. Because the display transformation is decreasing, its 25th percentile uses the 75th percentile of S and equals 30, so choice C is correct.
Setup
Setup
Write S as uniform on [a,a+d]. The gap between the reported percentile ranks determines the support width.
42−18=(0.80−0.20)d d=40,a=18−0.20(40)=10 Model
Model
The display is a decreasing affine transformation, so lower display quantiles correspond to upper raw-score quantiles.
QD(p)=50−0.5QS(1−p) Compute
Compute
Find the raw 75th percentile and transform it.
QS(0.75)=10+0.75(40)=40 QD(0.25)=50−0.5(40)=30 Answer
Answer
The display's 25th percentile is 30.
30(C)