Original practice · fully worked
Original variant: energy variability from triangular voltage
A calibration voltage V has density f(v)=v/8 for 0<v<4. A device records the energy index W=5V². Calculate Var(W).
- A
200/9 - B
1600/3 - C
5120/9 - D
6400/3 - E
6400
Answer and calculation
The triangular density gives E[V²]=8 and E[V⁴]=256/3. Thus Var(V²)=64/3, and scaling by 5 gives Var(W)=25(64/3)=1600/3, so choice B is correct.
Setup
Setup
Check the supplied density and write the two moments needed for the squared transformation.
∫048vdv=1 Var(W)=25Var(V2) Model
Model
Evaluate the second and fourth raw moments under the triangular density.
E[V2]=∫04v28vdv=8 E[V4]=∫04v48vdv=3256 Compute
Compute
Center the fourth moment and apply the squared scale factor.
Var(V2)=3256−82=364 Var(W)=52364=31600 Answer
Answer
The energy-index variance is 1600/3.
31600(B)