Independent solution

How to solve this Discrete Random Variables question

Setup

Setup

Use the tail-sum identity for a count supported from zero through five.

E⁡[X]=∑x=15Pr⁡(X≥x)\operatorname{E}[X]=\sum_{x=1}^{5}\Pr(X\ge x)

Model

Model

Insert the supplied square-root survival formula.

Pr⁡(X≥x)=12(1−x−15)\Pr(X\ge x)=\frac12\left(1-\sqrt{\frac{x-1}{5}}\right)

Compute

Compute

Evaluate and add the five survival values.

Pr⁡(X≥1,2,3,4,5)\Pr(X\ge1,2,3,4,5)
=0.500000, 0.276393, 0.183772, 0.112702, 0.052786=0.500000,\ 0.276393,\ 0.183772,\ 0.112702,\ 0.052786
E⁡[X]=1.125653506…\operatorname{E}[X]=1.125653506\ldots

Answer

Answer

The expected number of defective parts rounds to 1.1.

1.1(B)\boxed{1.1\quad\text{(B)}}