Independent solution

How to solve this Exponential Distribution question

Setup

Setup

An exponential lifetime has variance equal to the square of its mean. Each operating time therefore has variance 100.

E[X]=E[Y]=10E[X]=E[Y]=10
Var(X)=Var(Y)=102\operatorname{Var}(X)=\operatorname{Var}(Y)=10^2

Model

Model

The two operating times are independent, so the variance of their sum is the sum of their variances.

T=X+YT=X+Y
Var(T)=Var(X)+Var(Y)\operatorname{Var}(T)=\operatorname{Var}(X)+\operatorname{Var}(Y)

Compute

Compute

Adding the two equal contributions gives total variance 200.

Var(T)=100+100=200\operatorname{Var}(T)=100+100=200

Answer

Answer

The total operating time has variance 200, selecting choice E.

200(E)\boxed{200\quad\text{(E)}}