Independent solution

How to solve this Variance question

Setup

Setup

The additive constant has no effect on variance. Independence also removes the covariance cross term.

Z=3XY5Z=3X-Y-5
Var(X)=1,Var(Y)=2\operatorname{Var}(X)=1,\quad\operatorname{Var}(Y)=2

Model

Model

Each component variance is multiplied by the square of its coefficient, including the negative coefficient on the second component.

Var(Z)=32Var(X)+(1)2Var(Y)\operatorname{Var}(Z)=3^2\operatorname{Var}(X)+(-1)^2\operatorname{Var}(Y)

Compute

Compute

The two variance contributions are 9 and 2, giving total variance 11.

Var(Z)=9+2=11\operatorname{Var}(Z)=9+2=11

Answer

Answer

The independent linear combination has variance 11, selecting choice D.

11(D)\boxed{11\quad\text{(D)}}