This Exam P sample reference tests Independence. For the exponential amount, E[X]=8 and E[X²]=128. Independence and the Bernoulli indicator give E[Y]=0.45(8)=3.6 and E[Y²]=0.45(128)=57.6, hence Var(Y)=44.64 and choice E.
Write the payment as the product of the independent exponential amount and the zero-one payment indicator.
Y=ZX,Pr(Z=1)=0.45
Model
Model
Recover the first two raw moments of the exponential amount, then use Z squared equals Z.
E[X]=8,Var(X)=82=64
E[X2]=64+82=128
Z2=Z
Compute
Compute
Independence factors the product moments.
E[Y]=E[Z]E[X]=(0.45)(8)=3.6
E[Y2]=E[Z2]E[X2]=(0.45)(128)=57.6
Var(Y)=57.6−3.62=44.64
Answer
Answer
The payment variance is 44.64.
44.64(E)
Test the method on unseen problems
Probability Multivariate & Risk Models Practice Workbook
30 original multivariate random variables problems with complete solutions and wrong-choice analysis. Written for Exam P, not copied from the SOA set. One-time $19 PDF.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 12.96 is E[Y]²=(3.6)². It is the term subtracted from the second moment, not the variance by itself.
BThe value 15.84 is Var(E[Y|Z])=Var(8Z)=64(0.45)(0.55). It omits the variability of the exponential amount when payment occurs.
CThe value 28.80 is E[Var(Y|Z)]=0.45(64). It is only the within-indicator component in the law of total variance.
DThe value 35.20 weights the exponential variance by the no-payment probability, 0.55(64), instead of the payment probability and also omits the between-state component.
Original practice · fully worked
Original variant: correlation created by a processing gate
A job has a positive workload X with mean 10 and variance 25. Independently, a processing gate opens with probability 0.40; let Z be its zero-one indicator. The recorded workload is Y=ZX, so a closed gate records zero. Calculate the correlation between Z and Y.
A 0.4000
B 0.5367
C 0.6508
D 0.6928
E 0.8402
Answer and calculation
The gate gives Var(Z)=0.24, while E[Y]=4 and Var(Y)=34. Since ZY=Y, Cov(Z,Y)=4-0.40(4)=2.4, so Corr(Z,Y)=2.4/√(0.24 × 34)=0.8402, choice E.
Setup
Setup
Use the stated workload moments and the independent Bernoulli gate.
E[X]=10,Var(X)=25,Pr(Z=1)=0.40
Y=ZX
Model
Model
Find the recorded workload variance from its first two moments.
E[X2]=25+102=125
E[Y]=0.40(10)=4
E[Y2]=0.40(125)=50
Var(Y)=50−42=34
Compute
Compute
Because a zero-one indicator satisfies ZY=Z squared times X=Y, the cross moment is immediate.
Var(Z)=0.40(0.60)=0.24
Cov(Z,Y)=E[ZY]−E[Z]E[Y]=4−(0.40)(4)=2.4
Corr(Z,Y)=(0.24)(34)2.4=0.8401681
Answer
Answer
The gate and the recorded workload have correlation about 0.8402.