Independent solution

How to solve this Joint Distributions question

Setup

Setup

Let M be the larger of the two payments and collect joint cells that produce the same value.

M=max(X,Y)M=\max(X,Y)
Pr(M=0)=0.38\Pr(M=0)=0.38

Model

Model

A maximum of one comes from the three nonzero cells in the upper-left two-by-two block. Every cell containing a two contributes to the remaining mass.

Pr(M=1)=0.10+0.16+0.11=0.37\Pr(M=1)=0.10+0.16+0.11=0.37
Pr(M=2)=10.380.37=0.25\Pr(M=2)=1-0.38-0.37=0.25

Compute

Compute

Weight each possible maximum by its probability.

E[M]=0(0.38)+1(0.37)+2(0.25)\operatorname{E}[M]=0(0.38)+1(0.37)+2(0.25)
E[M]=0.87\operatorname{E}[M]=0.87

Answer

Answer

The expected larger payment is 0.87 in the table's units.

0.87(C)\boxed{0.87\quad\text{(C)}}