This Exam P sample reference tests Uniform Distribution. This problem reduces a conditional probability for a uniform lifetime to a ratio of interval lengths. The favorable tail has length 0.5 within a conditioned interval of length 3, so the probability is 1/6=0.166667 and choice B.
Let X have the stated uniform distribution. The later survival event is contained in the earlier survival event, so their intersection is simply the later event.
{X>4.5}⊂{X>2}
Pr(X>4.5∣X>2)=Pr(X>2)Pr(X>4.5)
Model
Model
Uniform probabilities are proportional to the lengths of the corresponding subintervals.
Pr(X>4.5)=5−05−4.5
Pr(X>2)=5−05−2
Compute
Compute
The common support length cancels in the conditional ratio.
Pr(X>4.5∣X>2)=(5−2)/5(5−4.5)/5
=30.5=61=0.1666666667
Answer
Answer
The requested conditional probability rounds to 0.17.
0.17(B)
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AThe value 0.10 is the unconditional tail probability (5-4.5)/5. It uses the full support rather than the shorter interval remaining after conditioning.
CThe ratio 2/4.5=0.444 compares the lower portions of two intervals and corresponds to the wrong-direction event P(X≤2 | X≤4.5), not the requested survival conditional.
DThe value 0.50 is only the raw length of the favorable interval from 4.5 to 5. A length is not yet a conditional probability until it is divided by the conditioned length 3.
EThe value 0.60 is P(X>2)=3/5, the probability of the conditioning event itself rather than the fraction of that event lying above 4.5.
Original practice · fully worked
Original variant: condition within a circular landing zone
A robotic probe lands uniformly within a circular testing plate centered at the origin. A reading is retained only when the horizontal coordinate is positive. Given that a reading is retained, calculate the probability that its vertical coordinate exceeds its horizontal coordinate.
A 0.125
B 0.250
C 0.500
D 0.750
E 0.875
Variant answer in brief
The positive-horizontal condition selects a semicircle with angular width pi. Requiring the vertical coordinate to exceed the horizontal one leaves the wedge from angle pi/4 to pi/2, with width pi/4, so the conditional probability is 1/4=0.250 and choice B.
Setup
Setup
Write a landing location in polar coordinates. Uniformity over the disk makes the probability of a full-radius sector proportional to its angle.
x=rcosθ,y=rsinθ
Model
Model
A positive horizontal coordinate selects the right semicircle. Within it, y>x selects a smaller wedge in the upper-right quadrant.
x>0⟺−2π<θ<2π
y>x⟺4π<θ<2πwithin the right semicircle
Compute
Compute
Divide the favorable angular width by the conditioned angular width.
Pr(y>x∣x>0)=π/2−(−π/2)π/2−π/4
=ππ/4=41=0.25
Answer
Answer
One quarter of the retained semicircle lies above the line y=x.
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