Independent solution

How to solve this Uniform Distribution question

Setup

Setup

Let X have the stated uniform distribution. The later survival event is contained in the earlier survival event, so their intersection is simply the later event.

{X>4.5}{X>2}\{X>4.5\}\subset\{X>2\}
Pr(X>4.5X>2)=Pr(X>4.5)Pr(X>2)\Pr(X>4.5\mid X>2)=\frac{\Pr(X>4.5)}{\Pr(X>2)}

Model

Model

Uniform probabilities are proportional to the lengths of the corresponding subintervals.

Pr(X>4.5)=54.550\Pr(X>4.5)=\frac{5-4.5}{5-0}
Pr(X>2)=5250\Pr(X>2)=\frac{5-2}{5-0}

Compute

Compute

The common support length cancels in the conditional ratio.

Pr(X>4.5X>2)=(54.5)/5(52)/5\Pr(X>4.5\mid X>2)=\frac{(5-4.5)/5}{(5-2)/5}
=0.53=16=0.1666666667=\frac{0.5}{3}=\frac16=0.1666666667

Answer

Answer

The requested conditional probability rounds to 0.17.

0.17(B)\boxed{0.17\quad\text{(B)}}