Independent solution

How to solve this Exponential Distribution question

Setup

Setup

Convert the supplied exponential rate to its survival function.

λ=0.0625=116\lambda=0.0625=\frac1{16}
S(x)=e−x/16S(x)=e^{-x/16}

Model

Model

Conditioning on survival to year five turns the upper endpoint into fifteen additional years.

Pr⁡(X<20∣X≥5)=1−Pr⁡(X≥20∣X≥5)\Pr(X<20\mid X\ge5)=1-\Pr(X\ge20\mid X\ge5)
Pr⁡(X≥20∣X≥5)=S(20)S(5)=e−15/16\Pr(X\ge20\mid X\ge5)=\frac{S(20)}{S(5)}=e^{-15/16}

Compute

Compute

Evaluate the residual lower-tail probability.

1−e−15/16=0.6083943733…1-e^{-15/16}=0.6083943733\ldots

Answer

Answer

The conditional probability rounds to 0.608.

0.608(C)\boxed{0.608\quad\text{(C)}}