Independent solution

How to solve this Exponential Distribution question

Setup

Setup

Convert the supplied exponential mean to a rate.

λ=10.50=2\lambda=\frac{1}{0.50}=2

Model

Model

Use memorylessness to replace the conditional lifetime with survival through only the additional interval.

Pr(T>0.70T>0.40)=Pr(T>0.700.40)\Pr(T>0.70\mid T>0.40)=\Pr(T>0.70-0.40)
=Pr(T>0.30)=\Pr(T>0.30)

Compute

Compute

Evaluate the exponential survival function at the remaining duration.

Pr(T>0.30)=e2(0.30)=e0.60\Pr(T>0.30)=e^{-2(0.30)}=e^{-0.60}
=0.5488116361=0.5488116361\ldots

Answer

Answer

The conditional probability rounds to 0.549.

0.549(D)\boxed{0.549\quad\text{(D)}}