Independent solution

How to solve this Loan Balances and Amortization question

Setup

Setup

Paying off five years early leaves 120 payments after the 180th payment rather than 180.

B180=2000a1200.005B_{180}=2000a_{\overline{120}|0.005}

Model

Model

Before the change, that same balance equals the present value of 180 original payments.

B180=Pa1800.005B_{180}=Pa_{\overline{180}|0.005}

Compute

Compute

The balance is 180146.91, the original payment is 1520.18, and its 360-payment present value is 253553.61.

L=Pa3600.005=253553.60533349L=Pa_{\overline{360}|0.005}=253553.60533349

Answer

Answer

The original loan was approximately 253,554, selecting choice A.

L253554(A)\boxed{L\approx253554\quad\text{(A)}}

Calculator reproduction

BA II Plus keystrokes

Check END/BGN, period, sign, TVM, and cash-flow setup

  1. 2ND · CLR TVM · 120 · N · 0.5 · I/Y · 0 · FV · 2000 · PMT · CPT · PVPV = -180146.91
  2. 180 · N · 180146.91 · +/- · PV · 0 · FV · CPT · PMTPMT = 1520.18
  3. 360 · N · 0 · FV · CPT · PVPV = -253553.61