This Exam FM sample reference tests Annuities. Treat each five-year interval as one period with effective rate 53.8624%. An arithmetic perpetuity with first payment 2 and increment 10 then has value 2/j + 10/j² = 38.18, choice E.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AChoice A (34.47) does not satisfy the arithmetic-perpetuity value at the effective five-year rate; no distinct standard one-step error is identifiable.
BChoice B (35.80) does not satisfy the arithmetic-perpetuity value at the effective five-year rate; no distinct standard one-step error is identifiable.
CChoice C (36.33) does not satisfy the arithmetic-perpetuity value at the effective five-year rate; no distinct standard one-step error is identifiable.
DChoice D (37.12) does not satisfy the arithmetic-perpetuity value at the effective five-year rate; no distinct standard one-step error is identifiable.
Original practice · fully worked
Original variant: arithmetic increment inferred from a spaced perpetuity price
A perpetuity pays every three years, beginning with 5 at year 3. Each later payment exceeds the preceding payment by a constant amount K. At a 4% annual effective yield, the perpetuity is priced at 168.32. Calculate K.
A 1.60
B 1.70
C 1.80
D 1.90
E 2.00
Variant answer in brief
The effective three-year rate is 12.4864%. Removing the level-payment component from the quoted price leaves K divided by that rate squared, giving K = 2.00, choice E.
Setup
Setup
Convert the annual yield to the effective rate for the three-year payment interval.
j=(1.04)3−1
Model
Model
Write the arithmetic perpetuity price as a level component plus an increasing component.
168.32=j5+j2K
Compute
Compute
Solving the linear equation gives increment K = 2.0000.
K=j2(168.32−j5)=2.00000000
Answer
Answer
The payment increment is 2.00, selecting choice E.
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