Original practice · fully worked
Original variant: locate a point inside a triangular region
A point (X,Y) is selected uniformly from the unit square. An observer is told that X+Y<1. Given this information, calculate the probability that both coordinates are less than 3/4.
- A
0.4375 - B
0.5000 - C
0.7500 - D
0.8750 - E
0.9375
Answer and calculation
The conditioning triangle has area 1/2. Requiring both coordinates below 3/4 removes two disjoint corner triangles, each of area 1/32, leaving area 7/16; the conditional ratio is (7/16)/(1/2)=7/8, choice D.
Setup
Setup
Uniform selection turns probability ratios into area ratios. The condition selects the lower-left half of the unit square.
C={(x,y):x+y<1} Area(C)=21 Model
Model
Within C, failure occurs when either coordinate is at least 3/4. Each failure region is a right triangle with leg length 1/4, and the two regions cannot overlap.
Area(x≥3/4, C)=21(41)2=321 Area(y≥3/4, C)=321 Compute
Compute
Remove both corner regions from the conditioning triangle, then divide by the conditioning area.
Area(x<3/4,y<3/4,C)=21−322=167 Pr(x<3/4,y<3/4∣C)=1/27/16=87=0.875 Answer
Answer
The requested conditional probability is 0.875.
0.8750(D)