This Exam P sample reference tests Uniform Distribution. The first uniform standard deviation gives b=9.60√(12). The second interval then has width 2b-6, so its standard deviation is (2b-6)/√(12)=17.468, which rounds to choice C.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThis applies the endpoint transformation directly to the first standard deviation, calculating 2(9.60) − 6 = 13.2. The subtraction changes the support width before division by √12.
BThis divides the six-unit width adjustment by √3 instead of √12, giving 19.2 − 6 / √3 = 15.736, near 15.7.
DThis ignores the six-unit reduction in the second support width and reports 2(9.60) = 19.2.
EA standard deviation of 19.9 would require a support width 19.9√12 = 68.94, but the recovered width is 2(33.2554) − 6 = 60.51.
Original practice · fully worked
Original variant: transform a symmetric dial error
A dial error U is uniformly distributed on the symmetric interval from -a to a. Its mean absolute error is 4 units. A corrected output is V=3U+2. Calculate the variance of V.
A 8
B 21.33
C 64
D 192
E 576
Variant answer in brief
For a symmetric uniform error, E|U|=a/2, so a=8 and Var(U)=a²⁄³=64/3. Scaling by 3 multiplies variance by 9, giving 192 and choice D.
Setup
Setup
Use symmetry to evaluate the mean absolute error in terms of the unknown half-width.
E[∣U∣]=2∫0au2a1du=2a
Model
Model
Recover the half-width and then the variance of a uniform variable on the symmetric support.
2a=4⟹a=8
Var(U)=12(2a)2=3a2=364
Compute
Compute
Apply the affine variance rule; the additive constant does not affect spread.
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