This Exam P sample reference tests Variance of Linear Combinations. The additive constant contributes no variance, and independence removes the covariance term. Squaring the two random coefficients gives 9(3)+4(4)=43, so choice D is correct.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 12 is Var(X)+Var(Y)+5=3+4+5. It ignores both random coefficients and incorrectly lets the fixed shift contribute.
BThe value 17 is 3Var(X)+2Var(Y)=3(3)+2(4). It scales variances by the coefficients instead of their squares.
CThe value 38 is 43-5. Subtracting a constant shifts the mean but does not subtract that constant from the variance.
EThe value 68 is 43+5 squared. It treats the fixed value -5 as an independent random term with variance 25.
Original practice · fully worked
Original variant: maximum variance under unknown dependence
The marginal variances of two calibration errors are Var(X)=4 and Var(Y)=25. Their correlation is not specified and may take any feasible value from -1 through 1. An index is defined as Z=3X-2Y+7. Calculate the largest possible value of Var(Z).
A 16
B 100
C 120
D 136
E 256
Variant answer in brief
Writing Cov(X,Y)=10rho gives Var(Z)=136-120rho. This is largest at rho=-1, where the variance is 256, so choice E.
Setup
Setup
Express covariance through the unknown correlation and the two standard deviations.
Cov(X,Y)=ρ(2)(5)=10ρ
Model
Model
Expand the variance, retaining the signed covariance cross term.
Var(Z)=32(22)+(−2)2(52)+2(3)(−2)(10ρ)
=136−120ρ
Compute
Compute
The expression decreases with correlation, so choose the smallest feasible correlation.
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