Independent solution

How to solve this Bayes’ Theorem question

Setup

Setup

Let d be the light-smoker death rate and express the other two conditional death rates as the stated multiples of d.

Pr(DN)=d/2,Pr(DL)=d,Pr(DH)=2d\Pr(D\mid N)=d/2,\quad \Pr(D\mid L)=d,\quad \Pr(D\mid H)=2d

Model

Model

Weight the three conditional death rates by their population shares to obtain the overall death probability.

Pr(D)=0.50(d/2)+0.30d+0.20(2d)=0.95d\Pr(D)=0.50(d/2)+0.30d+0.20(2d)=0.95d

Compute

Compute

The heavy-smoker death weight is 0.20(2d)=0.40d and the total is 0.95d; their ratio is 8/19.

Pr(HD)=0.40d/(0.95d)=8/19\Pr(H\mid D)=0.40d/(0.95d)=8/19

Answer

Answer

Given a death, the heavy-smoker probability rounds to 0.42, corresponding to choice D.

0.42(D)\boxed{0.42\quad\text{(D)}}