Independent solution

How to solve this Bayes’ Theorem question

Setup

Setup

Multiply the young-adult population share by its conditional collision probability to obtain its collision weight.

wY=(0.16)(0.08)=0.0128w_Y=(0.16)(0.08)=0.0128

Model

Model

Sum the four mutually exclusive age-group collision weights to obtain the total collision probability.

Pr(C)=0.08(0.15)+0.16(0.08)+0.45(0.04)+0.31(0.05)=0.0583\Pr(C)=0.08(0.15)+0.16(0.08)+0.45(0.04)+0.31(0.05)=0.0583

Compute

Compute

The young-adult weight is 0.0128 and the total collision probability is 0.0583, giving posterior probability 0.0128/0.0583=0.219554.

Pr(YC)=0.0128/0.0583=0.219554\Pr(Y\mid C)=0.0128/0.0583=0.219554

Answer

Answer

Given a collision, the young-adult probability rounds to 0.22, corresponding to choice D.

0.22(D)\boxed{0.22\quad\text{(D)}}