Independent solution

How to solve this Bayes’ Theorem question

Setup

Setup

For each age group, multiply its population share by its conditional accident probability to form an accident weight.

w=(0.06)(0.08)=0.0048w=(0.06)(0.08)=0.0048

Model

Model

The total accident probability is the sum of the four mutually exclusive group weights.

Pr(A)=0.0048+0.0045+0.0098+0.0112=0.0303\Pr(A)=0.0048+0.0045+0.0098+0.0112=0.0303

Compute

Compute

The youngest-group weight is 0.0048 and the total accident probability is 0.0303; Bayes' formula gives 0.0048/0.0303=0.158416.

Pr(16 ⁣: ⁣20A)=0.0048/0.0303=0.158416\Pr(16\!:\!20\mid A)=0.0048/0.0303=0.158416

Answer

Answer

Given an accident, the probability of the youngest group rounds to 0.16, which is choice B.

0.16(B)\boxed{0.16\quad\text{(B)}}