This Exam P sample reference tests Truncated Exponential Mean. Normalize the exponential density over the interval below 10 and integrate t against it. The resulting conditional mean is 5-10 exp(−2)/(1-exp(−2))=3.43482 years, which is choice E.
How to solve this Truncated Exponential Mean question
Setup
Setup
The mean of 5 gives rate 0.2, and the conditioning event has probability 1-exp(−2).
λ=0.2
Pr(T<10)=1−e−2
Model
Model
Write the conditional first moment as a truncated integral divided by the conditioning probability.
E[T∣T<10]=1−e−2∫010t(0.2)e−0.2tdt
Compute
Compute
Integration by parts gives a compact truncated-exponential mean formula.
E[T∣T<10]=5−1−e−210e−2
=3.4348235725
Answer
Answer
The conditional mean rounds to 3.435 years.
3.435(E)
Test the method on unseen problems
Probability Univariate Distributions Practice Workbook
30 original univariate random variables problems with complete solutions and wrong-choice analysis. Written for Exam P, not copied from the SOA set. One-time $19 PDF.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 0.865 is 1-exp(−2)=0.864665, the probability of the conditioning event rather than a conditional mean.
BThe value 1.157 is 1/(1-exp(−2))=1.156518, only the normalizing factor for the conditional density.
CThe value 2.568 is approximately (1-exp(−2)) times the unnormalized truncated first moment, multiplying by the conditioning probability instead of dividing.
DThe value 2.970 is the unnormalized moment integral from 0 to 10. It omits division by P(T<10)=1-exp(−2).
Original practice · fully worked
Original variant: tail-conditioned triangular mean
A diagnostic delay T has density f(t)=t/18 for 0<t<6 and zero elsewhere. Calculate the expected delay given that T exceeds 3.
A 0.7500
B 3.5000
C 4.0000
D 4.5000
E 4.6667
Answer and calculation
The tail probability is 3/4 and the truncated first moment is 7/2. Dividing gives E[T|T>3]=(7/2)/(3/4)=14/3=4.6667, choice E.
Setup
Setup
Compute the probability of the conditioning event from the density's cdf.
F(t)=36t2
Pr(T>3)=1−369=43
Model
Model
A conditional mean is a tail first moment divided by the tail probability.