Independent solution

How to solve this Shifted Exponential Distribution question

Setup

Setup

Separate the fixed lower endpoint from the exponential component.

X=5+Y,Y∼Exponential⁡(1/5)X=5+Y,\qquad Y\sim\operatorname{Exponential}(1/5)

Model

Model

The condition X at least 10 is equivalent to Y at least 5, after which memorylessness supplies a fresh exponential residual.

(X∣X≥10)=d10+Y′(X\mid X\ge10)\overset{d}=10+Y'
Y′∼Exponential⁡(1/5)Y'\sim\operatorname{Exponential}(1/5)

Compute

Compute

A deterministic shift does not affect variance, and an exponential variable with mean 5 has variance 25.

Var⁡(X∣X≥10)=Var⁡(Y′)\operatorname{Var}(X\mid X\ge10)=\operatorname{Var}(Y')
Var⁡(Y′)=52=25\operatorname{Var}(Y')=5^2=25

Answer

Answer

The conditional variance is 25.

25(C)\boxed{25\quad\text{(C)}}