Independent solution

How to solve this Normal Distribution question

Setup

Setup

Translate the variance relationship into the scale relationship used by normal quantiles.

σB2=2.25σA2\sigma_B^2=2.25\sigma_A^2
σB=1.5σA\sigma_B=1.5\sigma_A

Model

Model

The two distributions share a mean, so equate the two representations of the common percentile value.

μ+σAz0.14=μ+σBzp\mu+\sigma_A z_{0.14}=\mu+\sigma_B z_p
zp=z0.141.5z_p=\frac{z_{0.14}}{1.5}

Compute

Compute

Evaluate the lower-tail score and map the rescaled score back through the normal CDF.

z0.14=1.0803193z_{0.14}=-1.0803193
zp=0.7202129z_p=-0.7202129
p=Φ(0.7202129)=0.2356970p=\Phi(-0.7202129)=0.2356970

Answer

Answer

The matching percentile for the wider distribution is approximately 23.6.

23.6%(D)\boxed{23.6\%\quad\text{(D)}}