This Exam P sample reference tests Continuous Distributions. The density kernel has derivative exp(-x squared)(1-2x squared). Its interior maximum is at 1/√(2)=0.70711, which rounds to choice C.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe density kernel tends to zero at the lower boundary, so 0.00 is not a mode.
BThe value 0.50 results from solving 2x=1 after dropping the square in the derivative equation.
DThe value 0.84 is approximately 2⁽⁻¹⁄⁴⁾, which comes from replacing x squared by x to the fourth.
EAt x=1 the kernel is exp(-1)=0.36788, below its value 0.42888 at 1/√(2). The upper boundary is not the maximum.
Original practice · fully worked
Original variant: recover a density mode from its CDF
A normalized reliability score X has cumulative distribution F(x)=3x²-2x³ for 0≤x≤1, with F(x)=0 below zero and F(x)=1 above one. Determine the score at which the probability density is largest.
A 0.250
B 0.333
C 0.500
D 0.667
E 0.750
Variant answer in brief
Differentiating the CDF gives density 6x(1-x). Its derivative vanishes at x=1/2 and changes from positive to negative there, so choice C is the mode.
Setup
Setup
Differentiate the supplied cumulative distribution on the interior of its support.
f(x)=F′(x)=6x−6x2=6x(1−x)
Model
Model
Differentiate the density to find its interior stationary point.
f′(x)=6−12x
Compute
Compute
Solve for the critical score and compare it with the zero-density endpoints.
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