Original practice · fully worked
Original variant: recover a density mode from its CDF
A normalized reliability score X has cumulative distribution F(x)=3x²-2x³ for 0≤x≤1, with F(x)=0 below zero and F(x)=1 above one. Determine the score at which the probability density is largest.
- A
0.250 - B
0.333 - C
0.500 - D
0.667 - E
0.750
Answer and calculation
Differentiating the CDF gives density 6x(1-x). Its derivative vanishes at x=1/2 and changes from positive to negative there, so choice C is the mode.
Setup
Setup
Differentiate the supplied cumulative distribution on the interior of its support.
f(x)=F′(x)=6x−6x2=6x(1−x) Model
Model
Differentiate the density to find its interior stationary point.
f′(x)=6−12x Compute
Compute
Solve for the critical score and compare it with the zero-density endpoints.
6−12x=0⟺x=21 f(0)=f(1)=0,f(21)=23 Answer
Answer
The reliability density is maximized at 0.500.
0.500(C)