Independent solution

How to solve this Convolution question

Setup

Setup

Let G and B be the independent individual claim counts and T=G+B.

Pr(T=t)=gPr(G=g)Pr(B=tg)\Pr(T=t)=\sum_g\Pr(G=g)\Pr(B=t-g)

Model

Model

Compute the convolution masses for the central candidate totals.

Pr(T=1)=0.5(0.3)+0.3(0.2)=0.21\Pr(T=1)=0.5(0.3)+0.3(0.2)=0.21
Pr(T=2)=0.5(0.4)+0.3(0.3)+0.2(0.2)=0.33\Pr(T=2)=0.5(0.4)+0.3(0.3)+0.2(0.2)=0.33
Pr(T=3)=0.5(0.1)+0.3(0.4)+0.2(0.3)=0.23\Pr(T=3)=0.5(0.1)+0.3(0.4)+0.2(0.3)=0.23

Compute

Compute

Complete the distribution to verify the global maximum.

(Pr(T=0),,Pr(T=5))=(0.10,0.21,0.33,0.23,0.11,0.02)(\Pr(T=0),\ldots,\Pr(T=5))=(0.10,0.21,0.33,0.23,0.11,0.02)
maxtPr(T=t)=0.33=Pr(T=2)\max_t\Pr(T=t)=0.33=\Pr(T=2)

Answer

Answer

The total-count mode is 2.

2(C)\boxed{2\quad\text{(C)}}