Independent solution

How to solve this Poisson Mode and Tail question

Setup

Setup

A Poisson distribution has two adjacent modes only when its mean is the larger of those two modes. The stated modes therefore determine mean three.

modes 2,3λ=3\text{modes }2,3\Longrightarrow \lambda=3

Model

Model

The requested cutoff is the first integer whose upper tail is below 0.25. The tail beyond three is still approximately 0.35277.

Pr(N>3)=113e3=0.35277\Pr(N>3)=1-13e^{-3}=0.35277

Compute

Compute

The tail beyond four is approximately 0.18474, below 0.25. Comparing these adjacent cutoffs proves that four is minimal.

Pr(N>4)=1(13+8124)e3=0.18474<0.25\Pr(N>4)=1-\left(13+\frac{81}{24}\right)e^{-3}=0.18474<0.25

Answer

Answer

The smallest cutoff with tail below 25% is 4.

4(D)\boxed{4\quad\text{(D)}}