Independent solution

How to solve this Beta-Ratio Moments question

Setup

Setup

Substituting the odds transformation into the density reduces the first two moments to the displayed beta-type integrals.

E[Y]=6001x4(1x)dx=2E[Y]=60\int_0^1x^4(1-x)\,dx=2

Model

Model

The first integral gives mean two and the second gives second raw moment ten.

E[Y2]=6001x5dx=10E[Y^2]=60\int_0^1x^5\,dx=10

Compute

Compute

Variance is the second raw moment minus the squared mean, so the result is six.

Var(Y)=E[Y2]E[Y]2=104=6\operatorname{Var}(Y)=E[Y^2]-E[Y]^2=10-4=6

Answer

Answer

The transformed ratio has variance 6.

6(C)\boxed{6\quad\text{(C)}}