Independent solution

How to solve this Conditional Probability from a Density question

Setup

Setup

Because the event above ten is contained in the event above two, the conditional probability is the ratio of the two corresponding density integrals.

G(x)=x3330x2+800xG(x)=\frac{x^3}{3}-30x^2+800x

Model

Model

An antiderivative of the unnormalized density is sufficient because the unknown normalizing constant cancels between numerator and denominator.

Pr(X>10X>2)=G(20)G(10)G(20)G(2)\Pr(X>10\mid X>2)=\frac{G(20)-G(10)}{G(20)-G(2)}

Compute

Compute

Evaluate the antiderivative over the intervals above ten and above two. Their ratio is approximately 0.257202.

Pr(X>10X>2)=0.257202\Pr(X>10\mid X>2)=0.257202

Answer

Answer

The conditional exceedance probability rounds to 0.26.

0.26(D)\boxed{0.26\quad\text{(D)}}