Independent solution

How to solve this Inclusion–Exclusion question

Setup

Setup

Let G, B, and S denote the three events, and let U be the event that at least one of them occurs.

U=GBSU=G\cup B\cup S

Model

Model

Apply the three-event inclusion–exclusion formula: add the marginal probabilities, subtract all pairwise overlaps, and restore the triple overlap once.

Pr(U)=Pr(G)+Pr(B)+Pr(S)Pr(GB)Pr(GS)Pr(BS)+Pr(GBS)\Pr(U)=\Pr(G)+\Pr(B)+\Pr(S)-\Pr(G\cap B)-\Pr(G\cap S)-\Pr(B\cap S)+\Pr(G\cap B\cap S)

Compute

Compute

Substituting the seven supplied probabilities gives an at-least-one probability of 0.48.

Pr(U)=0.28+0.29+0.190.140.100.12+0.08=0.48\Pr(U)=0.28+0.29+0.19-0.14-0.10-0.12+0.08=0.48

Answer

Answer

The requested event is the complement of U, so its probability is 1 minus 0.48, or 0.52.

10.48=0.52(D)\boxed{1-0.48=0.52\quad\text{(D)}}