Original practice · fully worked
Original variant: nocturnal species detections
A field recorder is placed with equal probability in one of three habitat classes whose species capacities are 4, 7, and 10. Conditional on capacity C=c, the number R of distinct nocturnal species detected is uniformly distributed over the integers 0, 1, ..., c. Calculate the expected value of R.
- A
2.333 - B
3.000 - C
3.500 - D
7.000 - E
10.500
Answer and calculation
For a capacity c, the uniform count from 0 through c has mean c/2. Averaging the conditional means for capacities 4, 7, and 10 gives 3.5, so choice C is correct.
Setup
Setup
Represent the habitat capacity by C and the observed count by R.
Pr(C=4)=Pr(C=7)=Pr(C=10)=31 Model
Model
The mean of a discrete uniform distribution on the integers from 0 through c is the midpoint c/2.
E[R∣C=c]=20+c=2c Compute
Compute
Average the three conditional means with their equal habitat probabilities.
E[R]=31(24+27+210) E[R]=32+3.5+5=3.5 Answer
Answer
The recorder detects 3.5 distinct species on average.
E[R]=3.500(C)