This Exam P sample reference tests Continuous Random Variables. Integrating the density gives cumulative distribution 1 minus exp(-4x squared). Setting this equal to one-half yields a median of 0.416277, which rounds to choice C.
How to solve this Continuous Random Variables question
Setup
Setup
Integrate the density from zero to a positive argument to obtain its cumulative distribution.
FX(x)=∫0x8te−4t2dt=1−e−4x2,x>0
Model
Model
A continuous median m places one-half of the probability at or below m.
FX(m)=21
1−e−4m2=21
Compute
Compute
Isolate the exponential term, take logarithms, and retain the positive root because the support is positive.
4m2=log2
m=4log2=0.416277…
Answer
Answer
The median rounds to 0.416.
m≈0.416(C)
Test the method on unseen problems
Probability Univariate Distributions Practice Workbook
30 original univariate random variables problems with complete solutions and wrong-choice analysis. Written for Exam P, not copied from the SOA set. One-time $19 PDF.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 0.173 is log(2)/4, which is the computed value of m squared; taking the positive square root is still required.
BThe value 0.268 is approximately the first quartile, obtained by setting the cumulative probability to 0.25 instead of 0.50.
DThe value 0.693 reports log(2) itself, omitting both division by four and the square root.
EThe value 0.833 is √(log(2)); it takes the square root but fails to divide by two afterward.
Original practice · fully worked
Original variant: acoustic detection radius
The distance R, in kilometers, from an ocean sensor to a detected acoustic event has density 18r exp(-9r squared) for positive r and zero otherwise. Determine the 75th percentile of the detection distance.
A 0.278
B 0.333
C 0.392
D 0.462
E 0.680
Answer and calculation
The cumulative distribution is 1 minus exp(-9r squared). Equating it to 0.75 gives a percentile of 0.392470 kilometer, selecting choice C.
Setup
Setup
Integrate the density over its positive support.
FR(r)=∫0r18te−9t2dt=1−e−9r2
Model
Model
Let q be the 75th percentile and set its cumulative probability to 0.75.
1−e−9q2=0.75
Compute
Compute
Solve the exponential equation for the positive distance.
e−9q2=0.25
q=9log4=0.392470…
Answer
Answer
The 75th-percentile detection radius is approximately 0.392 kilometer.