This Exam P sample reference tests Exponential Distribution. The exponential memoryless property makes the elapsed event-free period irrelevant to the residual wait. Subtracting the survival probability beyond 25 days from the survival probability beyond 5 days gives 0.527656, which rounds to 0.53 and selects choice D.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AComputing the unconditional probability between absolute times 15 and 35 gives about 0.271 and fails to divide by the survival probability through the elapsed 10 days.
BThis is the exponential survival probability beyond one mean, exp(−1), and does not represent the bounded residual interval.
CThis is the complement of the desired interval probability, covering a residual wait at most 5 or at least 25 days.
EThis is approximately the probability that a fresh exponential wait is at most its mean, which replaces the two given residual bounds by a single 15-day cutoff.
Original practice · fully worked
Original variant: delayed calibration race
At a remote observatory, the time until a calibration routine completes is exponential with mean 8 minutes. An independent safety watchdog stops the routine after an exponential time with mean 12 minutes. Both clocks start together. Calculate the probability that calibration finishes first and finishes more than 3 minutes after the start.
A 0.214
B 0.321
C 0.535
D 0.600
E 0.687
Variant answer in brief
The two clocks race at combined rate 5/24. Integrating the calibration completion density after minute three while the watchdog survives gives (3/5) exp(−5/8)=0.321157, so choice B is correct.
Setup
Setup
Let C be the calibration completion time and W the independent watchdog time. Convert their means to rates.
C∼Exp(1/8),W∼Exp(1/12)
Model
Model
For calibration to finish first at time t, its density contributes while the watchdog must survive through t.
Pr(C<W,C>3)=∫3∞81e−t/8e−t/12dt
Compute
Compute
Combine the exponential rates and evaluate the tail integral.
81+121=245
Pr(C<W,C>3)=5/241/8e−(5/24)3
Pr(C<W,C>3)=53e−5/8=0.3211568571…
Answer
Answer
The delayed calibration-win probability rounds to 0.321.
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