Independent solution

How to solve this Variance and Standard Deviation question

Setup

Setup

Let W_i denote the amount in week i and let sigma be the common weekly standard deviation.

S=i=152WiS=\sum_{i=1}^{52}W_i
SD(Wi)=σ\operatorname{SD}(W_i)=\sigma

Model

Model

Because the weekly amounts are independent, their variances add in the annual total.

Var(S)=i=152Var(Wi)=52σ2\operatorname{Var}(S)=\sum_{i=1}^{52}\operatorname{Var}(W_i)=52\sigma^2

Compute

Compute

Square the stated annual standard deviation, solve for the weekly variance, and then take its positive square root.

32=52σ23^2=52\sigma^2
σ2=952\sigma^2=\frac{9}{52}
σ=352=0.4160251472\sigma=\frac{3}{\sqrt{52}}=0.4160251472\ldots

Answer

Answer

Each weekly amount has standard deviation 3 divided by the square root of 52.

352(D)\boxed{\frac{3}{\sqrt{52}}\quad\text{(D)}}