This Exam P sample reference tests Independence. Under independence, the no-claim probability is 0.9(0.7)=0.63. Under mutual exclusivity, the union probability is 0.10+0.30, leaving 0.60 for neither. Their difference is 0.03, so choice D is correct.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThis subtracts the independent overlap 0.10(0.30)=0.03 twice and attaches a negative sign, producing -0.06 instead of one overlap correction.
BThis is r-p=-0.03, so it reverses the requested subtraction.
CThis treats independence and mutual exclusivity as producing the same intersection structure; independence permits a 0.03 joint-claim probability.
EThis adds the 0.03 overlap correction twice. Only one inclusion-exclusion term separates the two no-claim probabilities.
Original practice · fully worked
Original variant: competing relay incidents
A data relay has probability 0.25 of an overload incident and probability 0.10 of an automatic restart during a shift. Under model I, the two events are independent. Under model II, every restart occurs during an overload. Calculate the probability that exactly one of these event types occurs under model I minus the corresponding probability under model II.
A -0.150
B 0.025
C 0.150
D 0.250
E 0.300
Variant answer in brief
Independence gives exactly-one probability 0.25(0.90)+0.75(0.10)=0.30. Under the nested model, exactly one means overload without restart, with probability 0.15. The difference is 0.15, so choice C is correct.
Setup
Setup
Let O denote overload and R denote restart.
Pr(O)=0.25,Pr(R)=0.10
Model
Model
Under independence, exactly one incident has two disjoint cases. Under the nested model, R is a subset of O, so only O without R qualifies.
qI=Pr(O∩Rc)+Pr(Oc∩R)
qII=Pr(O)−Pr(R)
Compute
Compute
Evaluate both model-specific probabilities.
qI=0.25(0.90)+0.75(0.10)=0.300
qII=0.25−0.10=0.150
qI−qII=0.150
Answer
Answer
The independence model has fifteen percentage points more exactly-one probability.
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