Original practice · fully worked
Original variant: covariance from a calibrated difference score
Two centered calibration readings U and V have variances 9 and 16. A diagnostic score is D=2U-V, and repeated trials show Var(D)=36. Calculate Cov(U,V).
- A
-4 - B
1/3 - C
4 - D
8 - E
16
Answer and calculation
Expanding Var(2U-V) gives 4(9)+16-4Cov(U,V)=36. Therefore Cov(U,V)=4, so choice C is correct.
Setup
Setup
Let c denote the covariance of the two calibration readings.
c=Cov(U,V) Model
Model
Expand the variance of the weighted difference, including its cross term.
Var(2U−V)=4Var(U)+Var(V)−4c Compute
Compute
Insert the three supplied variances and isolate c.
36=4(9)+16−4c=52−4c 4c=16⟹c=4 Answer
Answer
The two readings have covariance 4.
4(C)