Independent solution

How to solve this Mutually Exclusive Events question

Setup

Setup

Because C and D form a disjoint exhaustive pair, their intersections with A partition event A.

Pr(A)=Pr(AC)+Pr(AD)\Pr(A)=\Pr(A\cap C)+\Pr(A\cap D)

Model

Model

Subtract the supplied A-and-C cell from the A row total to recover the other cell in that row.

Pr(AD)=0.750.55=0.20\Pr(A\cap D)=0.75-0.55=0.20

Compute

Compute

Events A and B also form a disjoint exhaustive pair, so their intersections with D partition event D.

Pr(D)=Pr(AD)+Pr(BD)\Pr(D)=\Pr(A\cap D)+\Pr(B\cap D)
Pr(BD)=0.200.20=0\Pr(B\cap D)=0.20-0.20=0

Answer

Answer

No probability mass remains in the B-and-D cell.

0.00(A)\boxed{0.00\quad\text{(A)}}