This Exam P sample reference tests Expected Value. The five possible payments are 100, 200, 300, 350, and 400. Weighting them by probabilities 5/15 through 1/15 gives 220, choice C.
Original variant: variance of reimbursement under a nightly tariff
A short-stay plan reimburses 80 per night for the first two nights and 40 for the third night. Stay length N has probabilities 0.10, 0.30, 0.40, and 0.20 for zero, one, two, and three nights. Find the variance of the reimbursement.
A 128
B 3200
C 3584
D 3776
E 20160
Variant answer in brief
The payment mean is 128 and its second moment is 20,160. Subtracting 128² gives variance 3,776, choice D.
Setup
Setup
The reimbursement takes values zero, 80, 160, and 200 according to the stay length. Weighting these values gives mean 128.
Y∈{0,80,160,200},E[Y]=128
Model
Model
Compute the second raw moment by weighting the squared reimbursement values by the same stay probabilities.
E[Y2]=0.30(802)+0.40(1602)+0.20(2002)=20160
Compute
Compute
Subtract the squared mean from the second raw moment. The resulting variance is 3,776.
Var(Y)=20160−1282=3776
Answer
Answer
The reimbursement variance is 3,776, selecting choice D.
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