This Exam P sample reference tests Exponential Distribution. This is a shifted exponential distribution whose density is largest at its lower endpoint d. Its 10th percentile is d+beta ln(10/9), so the absolute gap from the mode is beta ln(10/9), which selects choice B.
How to solve this Exponential Distribution question
Setup
Setup
Subtract the lower endpoint to expose an ordinary exponential variable.
Y=X−d
fY(y)=β1e−y/β,y≥0
Model
Model
The exponential density decreases from its lower endpoint, so the mode of X is d. Write the CDF of the shifted variable for the percentile calculation.
mode(X)=d
FX(x)=1−e−(x−d)/β,x≥d
Compute
Compute
Set the CDF equal to 0.10 and solve for the percentile p.
0.10=1−e−(p−d)/β
e−(p−d)/β=0.90
p−d=−βln(0.90)=βln(910)
Answer
Answer
The lower endpoint cancels when the mode is subtracted from the percentile.
βln(910)(B)
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These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThis uses survival probability 10/11, which makes the lower-tail probability 1/11 rather than 0.10; that substitution produces beta ln(11/10).
CThis combines the wrong 1/11 lower-tail calculation with failure to subtract the mode d from the percentile.
DThis is the percentile location d+beta ln(10/9). The question asks for its difference from the mode d, so the shift must cancel.
EThis replaces the exponential scale beta by its reciprocal and also uses the wrong logarithmic ratio. The resulting expression has the wrong physical units for a loss difference.
Original practice · fully worked
Original variant: discrete mode–quantile gap
A service score K takes values 0, 1, 2, 3, and 4 with respective probabilities 1/16, 3/16, 6/16, 4/16, and 2/16. Calculate the absolute difference between the mode of K and its 75th percentile.
A 0 score units
B 1 score unit
C 2 score units
D 3 score units
E 5 score units
Variant answer in brief
The largest probability occurs at K=2. The CDF first reaches 0.75 at K=3, so the absolute difference is one and choice B.
Setup
Setup
Locate the modal score by comparing the five probability masses.
kmaxPr(K=k)=Pr(K=2)=166
mode(K)=2
Model
Model
For a discrete variable, the 75th percentile is the smallest score whose cumulative probability is at least 0.75.
FK(2)=161+3+6=1610=0.625
FK(3)=161+3+6+4=1614=0.875
Compute
Compute
The cumulative distribution crosses 0.75 at score three.
q0.75=3
∣q0.75−mode(K)∣=∣3−2∣=1
Answer
Answer
The mode and 75th percentile differ by one score unit.
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