Independent solution

How to solve this Bayes' Theorem question

Setup

Setup

Normalize the category probabilities from their stated ratios.

Pr(C)=c,Pr(A)=5c,Pr(B)=4c\Pr(C)=c,\quad \Pr(A)=5c,\quad \Pr(B)=4c
10c=1    (Pr(A),Pr(B),Pr(C))=(0.5,0.4,0.1)10c=1\implies (\Pr(A),\Pr(B),\Pr(C))=(0.5,0.4,0.1)

Model

Model

Multiply each category prior by its conditional zero-count probability.

wA=0.5(0.1)=0.05,wB=0.4(0.2)=0.08w_A=0.5(0.1)=0.05,\qquad w_B=0.4(0.2)=0.08
wC=0.1(0.4)=0.04w_C=0.1(0.4)=0.04

Compute

Compute

Normalize category C's contribution by the total probability of zero claims.

Pr(C0)=wCwA+wB+wC\Pr(C\mid 0)=\frac{w_C}{w_A+w_B+w_C}
=0.040.05+0.08+0.04=417=0.2352941176=\frac{0.04}{0.05+0.08+0.04}=\frac4{17}=0.2352941176\ldots

Answer

Answer

The conditional probability rounds to 0.235.

0.235(C)\boxed{0.235\quad\text{(C)}}