This Exam P sample reference tests Exponential Distribution. The exponential expenditure has variance 2000. Correlation 0.20 converts to covariance 1000, so the total variance is 2000+12500+2(1000)=16500 and choice D.
How to solve this Exponential Distribution question
Setup
Setup
Read the exponential scale as its mean and square it to obtain the first expenditure variance.
E[X]=205
Var(X)=(205)2=2000
Model
Model
Convert the supplied correlation to covariance using the two standard deviations.
Cov(X,Y)=0.20200012500
=0.20(5000)=1000
Compute
Compute
Expand the variance of the total, including both covariance cross terms.
Var(X+Y)=Var(X)+Var(Y)+2Cov(X,Y)
=2000+12500+2(1000)=16500
Answer
Answer
The total-expenditure variance is 16,500.
16500(D)
Test the method on unseen problems
Probability Multivariate & Risk Models Practice Workbook
30 original multivariate random variables problems with complete solutions and wrong-choice analysis. Written for Exam P, not copied from the SOA set. One-time $19 PDF.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 12,500 reports Var(Y) alone and omits both the exponential expenditure variance and the positive covariance contribution.
BThe value 13,500 is 12,500+1,000. It adds one covariance but omits Var(X) and the second covariance cross term.
CThe value 15,500 is 2,000+12,500+1,000. It includes both marginal variances but adds Cov(X,Y) only once instead of twice.
EUsing the square root of the correlation in the covariance formula gives Cov=sqrt[0.20(2000)(12500)]=2236.068. Then 2000+12500+2(2236.068)=18972.136, producing this choice.
Original practice · fully worked
Original variant: correlation between a balance and a contrast
Daily warehouse demand has two centered shocks. Shock X has variance 4 square units and shock Y has variance 25 square units, with correlation 0.30 between them. The warehouse tracks the balance U=X+Y and the contrast V=X-Y. Calculate Corr(U,V).
A -21.000
B -0.913
C -0.740
D 0.300
E 0.740
Answer and calculation
The original covariance is 3. The balance and contrast have variances 35 and 23, while their covariance is Var(X)-Var(Y)=-21. Normalization gives -21/√(805)=-0.740153 and choice C.
Setup
Setup
Convert the original correlation into covariance.
Cov(X,Y)=0.30(2)(5)=3
Model
Model
Expand the two transformed variances.
Var(U)=4+25+2(3)=35
Var(V)=4+25−2(3)=23
Compute
Compute
Find the covariance of the balance and contrast, then normalize it.
Cov(U,V)=Cov(X+Y,X−Y)=4−25=−21
Corr(U,V)=3523−21=−0.7401527457…
Answer
Answer
The balance and contrast have correlation approximately -0.740.