Original practice · fully worked
Original variant: exactly one independent sensor trigger
Three independent sensors trigger during a test with probabilities 0.25, 0.40, and 0.10. Calculate the probability that exactly one sensor triggers.
- A
0.010 - B
0.145 - C
0.405 - D
0.450 - E
0.595
Answer and calculation
The three disjoint one-trigger cases have probabilities 0.135, 0.270, and 0.045. Their sum is 0.450, choice D.
Setup
Setup
List the three mutually exclusive ways exactly one sensor can trigger.
ABˉCˉ,AˉBCˉ,AˉBˉC Model
Model
Use independence to multiply each trigger probability by the other two non-trigger probabilities.
Pr(exactly one)=0.25(0.60)(0.90)+0.75(0.40)(0.90)+0.75(0.60)(0.10) Compute
Compute
Evaluate and add the disjoint cases.
Pr(exactly one)=0.135+0.270+0.045=0.450 Answer
Answer
The probability of exactly one trigger is 0.45.
0.450(D)