Independent solution

How to solve this Inclusion-Exclusion question

Setup

Setup

Let A, B, and C denote the three listed home-feature sets.

∣A∣=130,∣B∣=280,∣C∣=150|A|=130,\qquad |B|=280,\qquad |C|=150

Model

Model

Apply three-set inclusion-exclusion using inclusive pair intersections.

∣A∪B∪C∣=∣A∣+∣B∣+∣C∣−∣A∩B∣−∣A∩C∣−∣B∩C∣+∣A∩B∩C∣|A\cup B\cup C|=|A|+|B|+|C|-|A\cap B|-|A\cap C|-|B\cap C|+|A\cap B\cap C|

Compute

Compute

Evaluate the union and take its complement in the portfolio.

∣A∪B∪C∣=130+280+150−40−30−50+10=450|A\cup B\cup C|=130+280+150-40-30-50+10=450
1000−450=5501000-450=550

Answer

Answer

There are 550 policies with none of the three features.

550(D)\boxed{550\quad\text{(D)}}