Independent solution

How to solve this Equation of Value under a Constant Force question

Setup

Setup

Index the forty deposits by n, with deposit n occurring at time n divided by two.

tn=n2,n=1,…,40t_n=\frac n2,\qquad n=1,\ldots,40

Model

Model

Write the balance at time 20 by accumulating each deposit under force 4.5%.

X=∑n=140700e0.045(20−n/2)X=\sum_{n=1}^{40}700e^{0.045(20-n/2)}

Compute

Compute

Multiply the equation by the twenty-year discount factor.

Xe−0.9=∑n=140700e−0.0225nXe^{-0.9}=\sum_{n=1}^{40}700e^{-0.0225n}

Answer

Answer

This index range and sign pattern are exactly those of choice E.

∑n=140700e−0.0225n=Xe−0.9(E)\boxed{\sum_{n=1}^{40}700e^{-0.0225n}=Xe^{-0.9}\quad\text{(E)}}