Independent solution

How to solve this Interest Rate Measures question

Setup

Setup

Integrate the linear force from time 0 to t.

a(t)=exp(0t(0.03+0.005r)dr)=exp(0.03t+0.0025t2)a(t)=\exp\left(\int_0^t(0.03+0.005r)\,dr\right)=\exp(0.03t+0.0025t^2)

Model

Model

The first deposit uses accumulation a(2); the second uses the forward factor from time 1 to time 2.

B2=100a(2)+100a(2)a(1)B_2=100a(2)+100\frac{a(2)}{a(1)}

Compute

Compute

The two contributions sum to 211.072018.

B2=211.07201783B_2=211.07201783

Answer

Answer

The account balance is approximately 211.07, selecting choice A.

B2211.07(A)\boxed{B_2\approx211.07\quad\text{(A)}}