This Exam P sample reference tests Linear Combinations of Independent Random Variables. Each observation has variance 9. Independence makes the variance of the linear combination equal to 3²(9)+9+9+9=108, so choice E is correct.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThis multiplies the first variance by the coefficient 3 rather than its square and also omits the remaining observations.
BThis treats all four coefficients as having magnitude one, giving four times the common variance.
CThis multiplies variance by the sum of coefficient magnitudes, 3+1+1+1=6, instead of by the sum of squared coefficients.
DThis includes only the contribution 3²Var(X1)=81 and omits the other three independent terms.
Original practice · fully worked
Original variant: calibration coefficient
Independent calibration errors A and B have variances 4 and 9. A combined error is Q=kA-B, where k is positive. The standard deviation of Q is 5. Calculate k.
A 1
B 2
C 4
D 5
E 8
Variant answer in brief
The target standard deviation gives variance 25. Independence yields Var(Q)=4k²+9, so 4k²+9=25 and the positive coefficient is k=2, which is choice B.
Setup
Setup
Convert the given standard deviation of the combined error to variance.
Var(Q)=52=25
Model
Model
Use independence and square the linear-combination coefficients.
Var(kA−B)=k2(4)+(−1)2(9)
Compute
Compute
Solve the variance equation and retain the specified positive coefficient.
The 3108-page Probability Proof Manual reorganizes 718 verified Exam P solutions by syllabus skill and adds formula proofs, error patterns, and original worked practice.