Independent solution

How to solve this Bayes Theorem question

Setup

Setup

Form the joint weights for the two possible groups and the observed five-year event.

wF=0.40(0.20)=0.08w_F=0.40(0.20)=0.08
wM=0.60(0.40)=0.24w_M=0.60(0.40)=0.24

Model

Model

Bayes' theorem normalizes the target group's joint weight by the sum of both compatible joint weights.

Pr(FE)=wFwF+wM\Pr(F\mid E)=\frac{w_F}{w_F+w_M}

Compute

Compute

Substitute and simplify the posterior probability.

Pr(FE)=0.080.08+0.24=14=0.25\Pr(F\mid E)=\frac{0.08}{0.08+0.24}=\frac14=0.25

Answer

Answer

The conditional probability is one fourth.

14(B)\boxed{\frac14\quad\text{(B)}}