Independent solution

How to solve this Joint Distributions question

Setup

Setup

Combine the requested adjacent masses into one rectangular event before using the cumulative table.

p(4,9)+p(5,9)=Pr(3<X5, 8<Y9)p(4,9)+p(5,9)=\Pr(3<X\le 5,\ 8<Y\le 9)

Model

Model

For a joint CDF, the probability inside a rectangle is the alternating sum of its four corner values.

Pr(a<Xb, c<Yd)=F(b,d)F(a,d)F(b,c)+F(a,c)\Pr(a<X\le b,\ c<Y\le d)=F(b,d)-F(a,d)-F(b,c)+F(a,c)

Compute

Compute

Insert the four cumulative probabilities at the rectangle corners.

p(4,9)+p(5,9)=F(5,9)F(3,9)F(5,8)+F(3,8)p(4,9)+p(5,9)=F(5,9)-F(3,9)-F(5,8)+F(3,8)
=0.840.650.67+0.53=0.05=0.84-0.65-0.67+0.53=0.05

Answer

Answer

The combined probability mass is 0.05.

0.05(E)\boxed{0.05\quad\text{(E)}}