Original practice · fully worked
Original variant: batches receiving exactly two review tags
A production batch may receive any of three review tags: thermal, vibration, and alignment. No batch receives all three tags. Historical rates are 0.55 for thermal, 0.50 for vibration, and 0.45 for alignment, while 0.90 of batches receive at least one tag. Calculate the probability that a batch receives exactly two tags.
- A
0.10 - B
0.50 - C
0.60 - D
0.90 - E
1.50
Answer and calculation
Let N count tags on a batch. Its mean is the sum of the three marginal rates, 1.50; because N can only be zero, one, or two, the tail-sum identity gives 1.50=P(N at least 1)+P(N at least 2)=0.90+P(N=2). Hence the answer is 0.60, choice C.
Setup
Setup
Let N be the number of tags attached to one batch and add the three indicator means.
N=IT+IV+IA E[N]=0.55+0.50+0.45=1.50 Model
Model
The prohibition on all three tags makes two the largest possible count. Apply the tail-sum identity for a bounded nonnegative integer variable.
E[N]=Pr(N≥1)+Pr(N≥2) Compute
Compute
Insert the probability of at least one tag and isolate the probability of two tags.
1.50=0.90+Pr(N≥2) Pr(N=2)=Pr(N≥2)=0.60 Answer
Answer
A batch receives exactly two tags with probability 0.60.
0.60(C)