This Exam P sample reference tests Sampling Without Replacement. This is a without-replacement complement calculation. The probability that both selected units come from the five non-target units is (5/9)(4/8), so the probability of selecting at least one of the four target units is 1-5/18=13/18, approximately 0.722 and choice E.
These notes identify the calculation error associated with each wrong letter when that error is reproducible.
AThe value 0.28 is the complementary probability 5/18 that neither selected unit is a target.
BThe value 0.31 is approximately (5/9)². It treats the two selections as if the first unit were replaced.
CThe value 0.56 is approximately 5/9, the probability that a single selection is non-target rather than the requested two-selection event.
DThe value 0.69 is approximately 1-(5/9)². It uses the correct complement idea but incorrectly assumes sampling with replacement.
Original practice · fully worked
Original variant: expected regions in a document sample
An archive has ten sealed reports: four concern the north region, three concern the south region, and three concern the central region. Three reports are selected uniformly without replacement. Calculate the expected number of different regions represented in the selection.
A 0.75
B 1.95
C 2.00
D 2.25
E 2.30
Variant answer in brief
Use one indicator for whether each region appears. The north is absent in C(6,3)/C(10,3) of selections, while each three-report region is absent in C(7,3)/C(10,3). Adding the three appearance probabilities gives 2.25, choice D.
Setup
Setup
Let I_N, I_S, and I_C indicate whether the north, south, and central regions appear, respectively.
R=IN+IS+IC,(310)=120
Model
Model
A region is absent exactly when all three reports are drawn from the other regions.
Pr(IN=0)=(310)(36)
Pr(IS=0)=Pr(IC=0)=(310)(37)
Compute
Compute
Apply linearity of expectation to the three appearance indicators.
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